Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 937: 35

Answer

$R = 89~\Omega$

Work Step by Step

We can find the resistance: $tan~\phi = \frac{X_L-X_C}{R}$ $R = \frac{X_L-X_C}{tan~\phi}$ $R = \frac{\omega_d~L-1/\omega_d~C}{tan~\phi}$ $R = \frac{2\pi~f~L-1/2\pi~f~C}{tan~\phi}$ $R = \frac{(2\pi)~(930~Hz)~(88\times 10^{-3}~H)-1/(2\pi)~(930~Hz)~(0.94\times 10^{-6}~F)}{tan~75^{\circ}}$ $R = 89~\Omega$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.