Answer
$\phi_{B2}=6$ mWb
Work Step by Step
We know that;
$\phi_{B2}=\frac{MI_1}{N_2}$
We plug in the known values to obtain:
$\phi_{B2}=\frac{1.67\times 10^{-3}(3.6)}{1}=6\times 10^{-3}=6$ mWb
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 30 - Induction and Inductance - Problems - Page 900: 73b
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