Answer
$B = 1.3\times 10^{-3}~T$
Work Step by Step
We can find the magnetic field strength at the center of the loop:
$B = \frac{\mu_0~i}{2r}$
$B = \frac{(4\pi\times 10^{-7}~H/m)~(100~A)}{(2)(0.050~m)}$
$B = 1.3\times 10^{-3}~T$
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