Answer
The energy stored in the coil is $~~1.96\times 10^{-4}~J$
Work Step by Step
In part (a), we found that $L = 97.9~H$
We can find the energy stored in the coil:
$U_B = \frac{i^2~L}{2}$
$U_B = \frac{(2.00\times 10^{-3}~A)^2~(97.9~H)}{2}$
$U_B = 1.96\times 10^{-4}~J$
The energy stored in the coil is $~~1.96\times 10^{-4}~J$
