Answer
$i_2 = 70.2~mA$
Work Step by Step
In part (a), we found that $i_1 = 23.4~mA$
We can find $i_2$:
$\frac{i_1}{i_2} = \frac{1}{3}$
$i_2 = 3~i_1$
$i_2 = (3)(23.4~mA)$
$i_2 = 70.2~mA$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 30 - Induction and Inductance - Problems - Page 900: 70b
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