Answer
The energy dissipated in the resistor is $~~13.6~J$
Work Step by Step
In part (a), we found that the energy delivered by the battery is $~~18.7~J$
In part (b), we found that the energy stored in the magnetic field is $~~5.10~J$
We can use conservation of energy to find the energy dissipated in the resistor:
$E = 18.7~J-5.10~J = 13.6~J$
The energy dissipated in the resistor is $~~13.6~J$
