Answer
$u=0.628\frac{J}{m^3}$
Work Step by Step
We can find the energy density as;
$u=\frac{B^2}{2\mu_{\circ}}$
We plug in the known values to obtain:
$u=\frac{(0.00125664)^2}{2\times 4\times 3.1416\times 10^{-7}}=0.628\frac{J}{m^3}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 30 - Induction and Inductance - Problems - Page 900: 66b
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