Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 3 - Vectors - Problems - Page 57: 7c

Answer

Displacement vectors must be perpendicular.

Work Step by Step

The general equation for the magnitude of resultant of two vectors is $R=\sqrt {A^{2}+B^{2}+2AB\cos\theta}$ Consider the case in which vectors are perpendicular. $\theta=90^{\circ}$ and $\cos\theta=0$, therefore the term $2AB\cos\theta$ disappears and the equation reduces to the form $R=\sqrt {A^{2}+B^{2}}$. In our case, when displacements are perpendicular $Resultant= \sqrt {(4\,m)^{2}+(3\,m)^{2}}=\sqrt {25\,m^{2}}=5\,m$
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