## Fundamentals of Physics Extended (10th Edition)

$130^{\circ}$
We have the value of $\vec{d}$ as; $\vec{d}=(-40.4\hat{i}+47.4\hat{j})\ m$ The direction of the vector is: $\theta = tan^{-1}(\frac{r_{y}}{r_{x}})$ $\theta = tan^{-1}(\frac{47.4\ m}{-40.4\ m})$ $\theta =-50^{\circ}+180 = 130^{\circ}$ with the +ve x axis