## Fundamentals of Physics Extended (10th Edition)

$-37.51^{\circ}$
We have the sum of three vectors as: $\vec{a}+\vec{b}+\vec{c}=(30.35\hat{i}-23.3\hat{j})\ m$ The direction of the vector is thus given by: $\theta= tan^{-1}(\frac{-23.3}{30.35})$ $\theta = -37.51^{\circ}$