Answer
$\text{The angle (counterclockwise from $+x$ axis) is $\tan ^{-1}(51.7 \mathrm{km} / 62.5 \mathrm{km})=40^{\circ},$ }$
$\text{which is to say that it points $40^{\circ}$ north of east. Although the resultant $\vec{r}$ is}$
$\text{shown in our sketch, it would be a direct line from the "tail' of $\vec{A}$ to the}$
$\text{"head" of $\vec{C}$ .}$
Work Step by Step
$\text{The angle (counterclockwise from $+x$ axis) is $\tan ^{-1}(51.7 \mathrm{km} / 62.5 \mathrm{km})=40^{\circ},$ }$
$\text{which is to say that it points $40^{\circ}$ north of east. Although the resultant $\vec{r}$ is}$
$\text{shown in our sketch, it would be a direct line from the "tail' of $\vec{A}$ to the}$
$\text{"head" of $\vec{C}$ .}$
