## Fundamentals of Physics Extended (10th Edition)

$127.02\ m$
We have: $\vec{a} = 43.30\ m\ \hat{i}+ 25\ m\ \hat{j}$ $\vec{b} = -48.30\ m\ \hat{i}+(-12.94\ m)\ \hat{j}$ $\vec{c} = 35.35\ m\ \hat{i}+(-35.35\ m)\ \hat{j}$ The value of the vector $\vec{a}-\vec{b}+\vec{c}$ can be found as: $\vec{a}-\vec{b}+\vec{c} = 43.30\ m\ \hat{i}+ 25\ m\ \hat{j}+48.30\ m\ \hat{i}+12.94\ m\ \hat{j}+35.35\ m\ \hat{i}-35.35\ m\ \hat{j}$ $\vec{a}-\vec{b}+\vec{c}=(127\hat{i}-2.60\hat{j})\ m$ $|\vec{a}-\vec{b}+\vec{c}| = \sqrt {127^2+2.60^2} = 127.02 m$