Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 3 - Vectors - Problems - Page 57: 3b



Work Step by Step

We use the following formula to find the angle: $\theta=arctan(\frac{A_{y}}{A_{x}})$ We plug in the known values to obtain: $=arctan(\frac{40.0m}{-25.0m})\approx-57.0^{\circ}$ The angle is in quadrant 2 because the vector has a negative $\hat{x}$ component and a positive $\hat{y}$ component. $\theta=180°-57.0^{\circ}\approx122°$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.