## Fundamentals of Physics Extended (10th Edition)

$-71.57^{\circ}$
We're given that; $\vec{a} = (3\,m)\hat{i}+(4\,m)\hat{j}$ and $\vec{b} = (5\,m)\hat{i}+(−2m)\hat{j}$. We can subtract these vectors component-wise; $\vec{b}-\vec{a} = (5\,m−3\,m)\hat{i}+(−2\,m−4\,m)\hat{j}$ $\vec{b}-\vec{a} =(2\,m)\hat{i}−(6\,m)\hat{j}$. The angle then equals: $\tan^{-1}(\frac{-6\,m}{2\,m}) = -71.57^{\circ}$.