Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 3 - Vectors - Problems - Page 57: 17e

Answer

$62\ m$

Work Step by Step

We have: $\vec{a} = 43.30\ m\ \hat{i}+ 25\ m\ \hat{j}$ $\vec{b} = -48.30\ m\ \hat{i}+(-12.94\ m)\ \hat{j}$ $\vec{c} = 35.35\ m\ \hat{i}+(-35.35\ m)\ \hat{j}$ Given that the condition is ($\vec{a}+ \vec{b})-(\vec{c}+\vec{d})=0$. From this, the value of $\vec{d}$ is $\vec{d} = \vec{a}+\vec{b}-\vec{c}$ Therefore; $ \vec{a}+\vec{b}-\vec{c}= 43.30\ m\ \hat{i}+ 25\ m\ \hat{j}-48.30\ m\ \hat{i}-12.94\ m\ \hat{j}-35.35\ m\ \hat{i}+35.35\ m\ \hat{j}$ $\vec{d}=(-40.4\hat{i}+47.4\hat{j})\ m $ $|\vec{d}| = \sqrt {40.4^2+47.4^2} = 62\ m $
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