Answer
$I=467mA$
Work Step by Step
In equilibrium state, the weight of the wire and magnetic force are equal in magnitude. Therefore:
$ILB=mg$
or $I=\frac{mg}{LB}$
We plug in the known values in this formula to obtain:
$I=\frac{0.013\times 9.81}{0.62\times 0.440}$
$I=0.467$
$I=467\times10^{-3}$
$I=467mA$
