Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 831: 33c

Answer

$R=1.51mm$

Work Step by Step

We know that, $R=\frac{mv}{qB}$ We plug in the known values in this equation to obtain: $R=\frac{9.109\times 10^{-31}(2.6507\times 10^7)}{1.6\times 10^{-19}(0.100)}$ $R=0.00151$ $R=1.51\times 10^{-3}$ $R=1.51mm$
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