Answer
$K.E=8.34\times 10^6eV$
Work Step by Step
$K.E=\frac{1}{2}mv^2$
But we know that,
$v=2\pi Rf$
So $K.E=\frac{1}{2}m(2\pi Rf)^2$
We plug in the known values to obtain:
$K.E=\frac{1}{2}(1.67\times 10^{-27})(2(3.1416)\times 0.530\times 12\times 10^6)^2$
$K.E=1.33\times 10^{-12}J$
$K.E=\frac{1.33\times 10^{-12}}{ 1.6\times 10^{-19}}eV$
$K.E=8.34\times 10^6eV$
