Answer
$200eV$
Work Step by Step
From law of conservation of energy,
$K.E=P.E$
i.e $\frac{1}{2}mv^2=qV$
Given that the potential energy is $200eV$ so the kinetic energy gained in each pass is also $200eV$.
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 28 - Magnetic Fields - Problems - Page 831: 35a
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