Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 831: 33b

Answer

$p=0.166mm$

Work Step by Step

We can determine the pitch from the formula: $p=vcos{\theta}T$................................eq(1) Also, we can find $v$ from the following equation $v=\sqrt{\frac{2K.E}{m}}$ Putting the values in this equation, we obtain $v$ as: $v=\sqrt{\frac{2(2\times 10^3\times 1.6\times 10^{-19})}{9.109\times 10^{-31}}}$ $v=2.6507\times 10^7\frac {m}{s}$ Now, we plug in the known values in eq(1) to obtain: $p=2.6507\times 10^7cos{89^{\circ}}(0.358\times 10^{-9})$ $p=1.66\times 10^{-4}$ $p=0.166\times 10^{-3}$ $p=0.166mm$
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