Answer
$K.E=3.32\times 10^7eV$
Work Step by Step
We can calculate the Kinetic energy of an emerging proton from:
$K.E=\frac{1}{2}mv^2$
But we know that
$v=2\pi Rf$
so $K.E=\frac{1}{2}m(2\pi Rf)^2$
We plug in the known values to obtain:
$K.E=\frac{1}{2}(1.67\times 10^{-27})(2\times 3.1416\times 0.530\times 2.39\times 10^7)^2$
$K.E=5.3069\times 10^{-12}J$
$K.E=\frac{5.3069\times 10^{-12}}{1.6\times 10^{-19}}eV$
$K.E=3.32\times 10^7eV$
