Answer
$F=28.2N$
Work Step by Step
We can find the magnetic force from the formula:
$F=iLBsin{\theta}$
We then plug in the known values in this formula to obtain:
$F=5000\times 100\times 60\times 10^{-6}sin 70^{\circ}$
$F=28.19 N$
After rounding it off, we obtain:
$F=28.2N$
