Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 831: 33a

Answer

$T=0.358ns$

Work Step by Step

We can find Time period from the formula: $T=\frac{2{\pi}m}{qB}$ We plug in the known values to obtain: $T=\frac{2(3.1416)(9.109\times 10^{-31})}{1.6\times 10^{-19}(0.100)}$ $T=0.35771\times 10^{-9}$ $T=0.358ns$
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