Answer
$W = 343 \space J$
Work Step by Step
Now, the work done to remove 1200 J from low temperature reservoir is
$|W| = \frac{|Q_L|}{K_C}$
where $K_C = \frac{T_L}{T_H - T_L} $
$K_C = \frac{280K}{360K - 280K} $
$K_C = 3.5$, so,
$|W| = \frac{1200J}{3.5}$
$W = 343 \space J$
