Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 606: 41

Answer

$P = 643.09 \space Btu/h $

Work Step by Step

When $K = 0.27 K_C$, Subsitute $K_C = \frac{T_L}{T_H - T_L} $ into $K$ $K = (0.27) ( \frac{T_L}{T_H - T_L} )$ $K = (0.27) (\frac{294.26 K}{ 307.04 K - 294.26 K})$ $ K = 6.22 $ To find the power, $P = \frac{W}{t} = \frac{Q_L/t}{k} $ $P =\frac{4000 Btu/h}{6.22} $ $P = 643.09 \space Btu/h $
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