Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 606: 33d

Answer

$ε=0.624 =62.4 $ %

Work Step by Step

The efficiency is : $ε = \frac{W}{Q_{in}} = \frac{9.18\times10^{2}J}{1.47\times10^{3}J}$ $ε=0.624$ $ε=62.4$ %
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