Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 606: 38

Answer

$ P = 436.11 W$

Work Step by Step

The equation for work done if the temperature is unknown is $|W| = \frac{|Q_H|}{K + 1}$ In one hour, $Q_H = 7.54 \times 10^6 J $ and $ K = 3.80$ $|W| = \frac{7.54 \times 10^6 J}{3.80 + 1}$ $ |W| = 1.57 \times 10^{6} J$ The rate of work done means the $power$ $ P = \frac{|W|}{\Delta t}$ $ P = \frac{1.57 \times 10^{6} J}{3600 s}$ $ P = 436.11 W$
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