Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 606: 35a

Answer

$\frac{T_2}{T_1} = 3.00$

Work Step by Step

Pressure at 2 is $p_2 = 3.00p_1$ Volume 2 is $V_2 = V_1 = \frac{nRT_1}{p_1} $ and $T_2 = \frac{p_2V_2}{nR} = \frac{3.00p_1V_1}{nR} = 3.00T_1$ $T_2 = 3.00T_1$ $\frac{T_2}{T_1} = 3.00$
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