Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 606: 44a

Answer

$W = 167 \space J $

Work Step by Step

The carnot efficiency is $\epsilon = 1 - |\frac{T_L}{T_H}|$ $\epsilon = 1 - |\frac{280K }{360 K}| $ $\epsilon = 0.222$ To find the work done, $W = \epsilon Q$ $W = (0.222) (750 J)$ $W = 167 \space J $
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