Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 606: 40b

Answer

$|W| = 7.4 kJ$

Work Step by Step

To find the work per cycle, |W|, $|W| = |Q_H| - |Q_L| $ $|W| = 49.37 kJ - 42.0 kJ $ $|W| = 7.4 kJ$ The answer is rounded off to the nearest one decimal place.
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