Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 606: 42

Answer

$Q_L=1.08\times 10^6J$

Work Step by Step

We know that: $|W|=Pt=(200W)(10.0 min)(60\frac{s}{min})=1.20\times 10^5J$ We also know that: $|Q_L|=K|W|$ but $K=\frac{T_L}{T_H-T_L}$ $\implies |Q_L|=\frac{T_L|W|}{T_H-T_L}$ We plug in the known values to obtain: $Q_L=\frac{270(1.20\times 10^5)}{300-270}=1.08\times 10^6J$
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