Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 604: 7c

Answer

$$+1.72 \mathrm{\ J} / \mathrm{K} $$

Work Step by Step

The change in entropy is $$ \begin{aligned} \Delta S &=\Delta S_{1}+\Delta S_{2}=m_{1} c_{1} \ln \left(\frac{T_{f}}{T_{i, 1}}\right)+m_{2} c_{2} \ln \left(\frac{T_{f}}{T_{i, 2}}\right) \\ &=(50.0 \mathrm{g})(386 \mathrm{J} / \mathrm{kg} \cdot \mathrm{K}) \ln \left(\frac{320 \mathrm{K}}{400 \mathrm{K}}\right)+(100 \mathrm{g})(128 \mathrm{J} / \mathrm{kg} \cdot \mathrm{K}) \ln \left(\frac{320 \mathrm{K}}{200 \mathrm{K}}\right) \\ &=+1.72 \mathrm{\ J} / \mathrm{K} \end{aligned} $$
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