Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 604: 5b

Answer

$\Delta S = 173.2\ J/K$

Work Step by Step

Formula for the change in entropy is: $\Delta S = \int_i^f \frac{dQ}{T}= \int_i^f\frac{mC\Delta T}{T} = mCln\frac{T_f}{T_i} $ Now, $T_i = 25+273.16 = 298.16 K$ and $ T_f =100+273.16 = 373.16 K $ Now, we find the change in entropy: $\Delta S = 2\times386\times ln\frac{373.16}{298.16}=173.2\ J/K$
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