Answer
$\Delta S_2=24.9\frac{J}{K}$
Work Step by Step
We can find entropy change of water as:
$\Delta S_2=\int _{Q_i}^{Q_f}\frac{dQ_2}{T}=\int _{Q_i}^{Q_f} \frac{m_2c_2 dT}{T}=m_2c_2ln \frac{T}{T_{i2}}$
We plug in the known values to obtain:
$\Delta S_2=0.05(4187)\ln \frac{330}{293}=24.9\frac{J}{K}$
