Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 604: 1c

Answer

$\Delta S = 0$

Work Step by Step

In adiabatic expansion no heat can enter or leave the system. This means that; $\Delta Q = 0$ Therefore we substitute $\Delta Q = 0$ in the formula for entropy below and find that; Entropy $\Delta S = \frac{\Delta Q}{T}$ $\Delta S = 0$
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