Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 604: 14d

Answer

$\Delta S = 8.64 J/K$

Work Step by Step

The equation of entropy in thermodynamics is $\Delta S = nC_V ln (\frac{T_c}{T_b})$ and $C_V = \frac{3}{2} R$ Taking from (b), $T_b = \frac{4.0p_oV_o }{nR} $ and $T_c = \frac{8.0p_oV_o }{nR}$. Substitute into entropy equation $\Delta S = n(\frac{3}{2} R) ln (\frac{\frac{8.0p_oV_o }{nR}}{\frac{4.0p_oV_o }{nR}})$ $\Delta S = n(\frac{3}{2} R) ln (\frac{8.0}{4.0})$ $\Delta S = (1)\frac{3}{2} (8.31 J/K) ln (2)$ $\Delta S = 8.64 J/K$
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