Answer
$Q= 5.7\times 10^4\ J$
Work Step by Step
The formula for the specific heat is $Q=mC\Delta T$
where
Q= heat energy (J)
m= mass of a substance (kg)
C = specific heat (J/kg.K)
$\Delta T$ = change in temperature
Given that;
specific heat C = 386 J/(kg.K)
mass m = 2 kg
change in temperature $ \Delta T = T_2 - T_1 = 100 - 25 = 75^{\circ} C $
So the energy absorbed as heat Q is:
$Q=mC\Delta T$
$Q=2 \times 386\times 75=57900\ J = 5.7\times 10^4\ J$
