Answer
$T=0.63s$
Work Step by Step
To find the period of a mass-spring, system use the fact that the angular frequency $\omega$ is equal to $$\omega=\sqrt{\frac{{k}}{m}}$$ Substituting known values of $k=130N/m$ and $m=1.3kg$ yields an omega value of $$\omega=\sqrt{\frac{130N/m}{1.3kg}}=10. rad/s$$ Use the relation between between period T and angular frequency $$T=\frac{2\pi}{\omega}$$ Substitute the known value of $\omega=10.rad/s$ yields a period of $$T=\frac{2\pi}{10.rad/s}$$ $$T=0.63s$$
