Answer
$k_1 = 21,000~N/m$
Work Step by Step
Let $L$ be the original length of the spring.
We can find $k_1$:
$\frac{7.0}{17} L~k_1 = k~L$
$k_1 = \frac{17}{7.0}k$
$k_1 = (\frac{17}{7.0})~(8600~N/m)$
$k_1 = 21,000~N/m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 15 - Oscillations - Problems - Page 440: 66a
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