Answer
$k_2 = 15,000~N/m$
Work Step by Step
Let $L$ be the original length of the spring.
We can find $k_2$:
$\frac{10}{17} L~k_2 = k~L$
$k_2 = \frac{17}{10}k$
$k_2 = (\frac{17}{10})~(8600~N/m)$
$k_2 = 15,000~N/m$
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