Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 440: 66b

Answer

$k_2 = 15,000~N/m$

Work Step by Step

Let $L$ be the original length of the spring. We can find $k_2$: $\frac{10}{17} L~k_2 = k~L$ $k_2 = \frac{17}{10}k$ $k_2 = (\frac{17}{10})~(8600~N/m)$ $k_2 = 15,000~N/m$
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