Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 440: 71b

Answer

$x_m=1.19cm$

Work Step by Step

We know that $v_m=x_m{\omega}$, where $v_m$ and $\omega$ represent maximum speed and maximum displacement i.e amplitude respectively. The above equation simplifies to: $x_m=\frac{v_m}{\omega}$ We plug in the known values to obtain: $x_m=\frac{0.15}{4\pi}=0.0119m=1.19cm$
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