Answer
$v_{max}=2.1\frac{m}{s}$
Work Step by Step
We know that,
$v_{max}=x_m{\omega}$
where $v_{max}$ and $x_m{\omega}$ represent maximum speed and maximum displacement respectively.
We plug in the known values in this formula to obtain:
$v_{max}=0.00075(2.8\times 10^3)=2.1\frac{m}{s}$
