Answer
$v_m=7.2\frac{m}{s}$
Work Step by Step
We know that,
$v_m=x_m{\omega}$
where $x_m$ and $v_m$ represent amplitude and maximum speed.
As $\omega=2{\pi}f$ and $f=\frac{180}{60}=3Hz$,
hence $v_m=x_m2{\pi}f$
We plug in the known values to obtain:
$v_m=(0.38)(2\pi)()3=7.2\frac{m}{s}$
