Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 440: 65a

Answer

$\omega=2.8\times 10^3\frac{rad}{s}$

Work Step by Step

We know that, $\omega=2{\pi}f$ We plug in the known values in this formula to obtain: $\omega=2(3.1416)(440)=2.8\times 10^3\frac{rad}{s}$
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