Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 440: 68a

Answer

$K=147\frac{N}{m}$

Work Step by Step

We know that, $F=Kx$ This can be written as; $K=\frac{F}{x}$ In the given scenario: $F=mg$ So, $K=\frac{mg}{x}$ We plug in the known values to obtain: $K=\frac{0.300(9.8)}{0.0200}=147\frac{N}{m}$
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