Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 12 - Equilibrium and Elasticity - Problems - Page 348: 36b

Answer

$F_v = 170~N$

Work Step by Step

The vertical forces on the fingers are equal and opposite to the climber's weight. We can find $F_v$: $4~F_v = mg$ $F_v = \frac{mg}{4}$ $F_v = \frac{(70~kg)(9.8~m/s^2)}{4}$ $F_v = 170~N$
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