Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 12 - Equilibrium and Elasticity - Problems - Page 348: 34a

Answer

$T = \frac{W~x}{L~sin~\theta}$

Work Step by Step

We can consider the net torque about the rotation axis at the hinge. The torque due to the box's weight must be equal in magnitude to the torque due to the tension in the wire. We can find an expression for the tension: $L~T~sin~\theta = mg~x$ $L~T~sin~\theta = W~x$ $T = \frac{W~x}{L~sin~\theta}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.