Answer
$F = 315~N$
Work Step by Step
The box will roll about a rotation axis at one of the bottom edges of the box.
To find the minimum required force, we can apply the force at the diagonally opposite edge of the box from the the rotation axis, such that the vector of the applied force makes a $90^{\circ}$ angle to the direction of the rotation axis.
Let $L$ be the length of each side of the box.
To find the minimum required force, we can assume that the torque due to the applied force is equal and opposite to the torque due to the box's weight:
$\sqrt{2}~L~F = (\frac{L}{2})(mg)$
$F = \frac{mg}{2~\sqrt{2}}$
$F = \frac{890~N}{2~\sqrt{2}}$
$F = 315~N$
