Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 12 - Equilibrium and Elasticity - Problems - Page 348: 33a

Answer

$\theta = 60^{\circ}$

Work Step by Step

When $\frac{y}{L} = 0$, the force $F_a$ is applied at the location of the hinge. Since $T = 0$ when $\frac{y}{L} = 0$, then the force $F_h$ is equal and opposite to the force $F_a$. Note that $F_h = 300~N$ when $\frac{y}{L} = 0$ We can consider the point $\frac{y}{L} = 1$ to find the angle $\theta$: $T~cos~\theta = 300~N$ $(600~N)~cos~\theta = 300~N$ $cos~\theta = 0.5$ $\theta = cos^{-1}~(0.5)$ $\theta = 60^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.