Answer
The normal force on each front wheel is $~~3100~N$
Work Step by Step
In part (b), we found that the total normal force on the rear wheels is $4714~N$
The sum of the normal forces on the rear wheels and the front wheels is equal to the car's weight.
We can find the normal force on each front wheel:
$2~F_N+4714~N = 11,000~N$
$F_N = \frac{11,000~N-4714~N}{2}$
$F_N = 3100~N$
The normal force on each front wheel is $~~3100~N$
